Answer by You can put this solution on YOUR website!Multiply 5 y 9 1 6 x 3 times 8 0 x 2 y 5 by multiplying numerator times numerator and denominator times denominator Cancel out 16y^ {5} in both numerator and denominator Cancel out 1 6 y 5 in both numerator and denominator To multiply powers of the same base, add their exponents Add 2 and 3Then a 3 b 3 c 3 3abc = 0 or a 3 b 3 c 3 = 3abc
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Solve the following system of equations for x, y and z 7x5y3z = 16 (1) 3x5y2z =8 (2) 5x3y7z = 0 (3) Answer Solution We are going to show you how to solve this system of equations three different ways 1) Substitution, 2) Elimination 3) Matrices SUBSTITUTION The process of substitution involves several stepsGet stepbystep solutions from expert tutors as fast as 1530 minutesSimplify algebraic expressions stepbystep \square!
2x 3 (yx) 2 D (yx) = 0 , 2x 3 (yx) 2 (y'1) = 0 , so that (Now solve for y' ) 2x 3 (yx) 2 y' 3 (yx) 2 = 0 , 3 (yx) 2 y' = 3 (yx) 2 2x, and Thus, the slope of the line tangent to the graph at (1, 3) is , and the equation of the tangent line is y ( 3 ) = (5/6) ( x ( 1 ) ) , or y = (5/6) x (13/6) Click HERE to return to Added PM This answer has been confirmed as correct and helpful 5 jomar07 Simplify (2x 3) (x 4) Solution Using Foil Method (2x 3) (x 4) = 2x^2 8x 3x 12 = 2x^2 5x 12Algebra Factor x^3y^3 x3 − y3 x 3 y 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2)
1 Find the distance from the point (1, 4, 1) to the plane 2x3y z = 1 We need to nd some vector to the plane, for which we need a point in the plane If we pick x = 0 and y = 0, we get z = 1, so z = 1 Thus, (0;0;1) is a point in the plane Then we can compute a vector from the point to the plane as 2 4 1 4 1 3 5 2 4 0 0 1 3 5= 2 4 1 4 0 3 5Xx = x Proof x x = (x x) 1 postulate 2(b)Your answer would be x^4yz/3 so simplified it would be 3x^4y^4z^2/6y^3z^3 Now simplify the z's bring z^3 to the numerator And get 3 x^4 y^4 z^2 (z^3) /6y^3 z^2 (z^3) is z because when multiplying your exponents add or subtract depending on whether a number is negative or positive In this problem its like (23)= 1 and z^1 is z
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Y z 1 Example 5608 3 Find @z @x for x 2y z 2z =4 Let's use the information from example 2 All we need to find is Fx =2x Then @z @x = 2x 2z 2 = x z 1 • Sometimes x and y are functions of one or more parameters We may find the derivative of a function with respect to that parameter using the chain rule • The formulas for3 Integrate both sides Z 1 f(y) dy = Z g(x) dx This gives us an implicit solution 4 Solve for y (if possible) This gives us an explicit solution 5 If there is an initial condition, use it to solve for the unknown parameter in the solution function 6 Check for any constant singular solutions Remember they must satisfy both the DE and341 Digital Circuits and Their Relationship to Boolean Algebra 134 • More complex Boolean expressions can be represented as combinations of AND, OR, and NOT gates, resulting in a logic diagram that describes the entire expression FIGURE 39 A Logic Diagram for F(x, y, z) = x y'z 342 Integrated Circuits 136 •
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Z= 1 2t is parallel to the plane 2x 3y 4z= 5 Solution A line is parallel to the plane if it is perpendicular to a normal vector to the plane A normal vector to the plane is given by h2;3;4iand the direction of the line is given by the vectorFirst type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More ExamplesHow do you simplify #(2^3 *3^2) / (2^4 * 3^2)^2#?
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Section 35 Minterms, Maxterms, Canonical Form & Standard Form Page 2 of 5 A maxterm, denoted as Mi, where 0 ≤ i < 2n, is a sum (OR) of the n variables (literals) in which each variable is complemented if theA = axiayjazk (314) where ax = dvx dt = d2x dt2 ay = dvy dt = d2y dt2 az = dvz dt = d2z dt2 (315) 314 Constant Acceleration in Two Dimensions When the acceleration a (for motion in two dimensions) is constant we have two sets of equations to describe the x and y coordinates, each of which is similar to the equations inY = 3 Parabola z = x2 9 (d) Sketch all the traces that you found in part (c) on the same coordinate axes 5 (e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of
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((3 • (x y z) x 3) y 3) z 3 Step 2 Trying to factor by pulling out 21 Factoring x 3 3xy 3 3yz 3 3z Thoughtfully split the expression at hand into groups, each group having two terms Group 1 y 3 3y Group 2 x 3 3x Group 3 z 3 3z Pull out from each group separately Group 1 (y 23) • (y) Group 2 (x 23Steps for Solving Linear Equation y = 2x3 y = 2 x 3 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x3=y 2 x 3 = y Subtract 3 from both sides Subtract 3 from both sidesSimplify (x y) 3 (x y) 3 Simplifying Mathematical Expressions There are a number of different types of mathematical expressions in the study of mathematics
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In this math video lesson on Adding and Subtracting Radical Expressions, I simplify 3√√2 #simplify #radicalexpression #minutemathEvery Month we have a ne Simplify ((x^2 y^3 z^(2) )^(3) (x^(3) yz^3 )^(1/2))/(xyz^(3) )^(5/2)"x or y" The truth table for OR is shown in Table 32 TABLE 32 The Truth Table OR Both x and x' are read as "NOT x" The truth table for NOT is shown in Table 33 TABLE 33 The Truth Table for NOT The rule of precedence for Boolean operators give NOT top priority, followed by AND, and then OR TABLE 34 The Truth Table for F(x, y, z
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No integers x;y;z with xyz6= 0 satisfy x3 y3 z3 = 0 Proof We may assume that x, y, and zare pairwise coprime If xyzis not divisible by 3, then the equation has no solution even in Z=(9), where every nonzero cube is 1 Suppose then, without loss of generality, that 3jz We will work in the UFD R= Z with = ( 1i p 3)=2, a root of theSimplify (X^2 Y^2)^3 (Y^2 Z^2)^3 (Z^2 X^2)^3/(X Y)^3 (Y Z)^3 (Z X)^3EXAMPLE 1415 Suppose the temperature at (x,y,z) is T(x,y,z) = e−(x2y2z2) This function has a maximum value of 1 at the origin, and tends to 0 in all directions If k is positive and at most 1, the set of points for which T(x,y,z) = k is those points satisfying x 2y2 z = −lnk, a sphere centered at the origin The level surfaces are the
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Harnett, ch 3) A The expected value of a random variable is the arithmetic mean of that variable,EE 10 Fall 10 3 Implement the following Boolean functions with a multiplexer (a) F(w,x,y,z) = Σ(2,3,5,6,11,14,15) w x y z F 0 0 0 0 0 F = 0 Simplify 1 5√6 √24 A 3√6 2 Evaluate 3y 5xy x for x = 4 and y = 2 A 42 3 Simplify 3x(5y 4) 2xy 10x 6x^2 A 3xy 2x 6x^2 4 Evaluate 5^3 A 1/125 5 Simplify ((2x^4y^7)/(x^5))^3 Assume all variables Algebra Translate the phrase to mathematical language
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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, musicIn this math video lesson on Multiplying Radical Expressions, I simplify √3(5√3) #simplify #radicalexpressions #minutemathEvery Month we have a new GIVEAWAYCprE 210 Lec 15 1 • Multiplexers are circuits which select one of many inputs • In here, we assume that we have onebit inputs (in general, each input may have more than one bit) • Suppose we have eight inputs I0, I1, I2, I3, I4, I5, I6, I7 • We want one of them to be output based on selection signals • 3 bits of selection signals to decide which input goes to output
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For &ve variables x;y;z;t;s Two lines intersect each other if and only If this system has a solution If, for instance, (x0;y0;z0;t0;s0)is a solution, then the &rst three components, (x0;y0;z0)is a point of intersection 4 We now proceed to solution the system by eliminating x,y,zAlgebra Calculator is a calculator that gives stepbystep help on algebra problems See More Examples » x3=5 1/3 1/4 y=x^21 Disclaimer This calculator is not perfect Please use at your own risk, and please alert us if something isn't working Thank you2 We can describe a point, P, in three different ways Cartesian Cylindrical Spherical Cylindrical Coordinates x = r cosθ r = √x2 y2 y = r sinθ tan θ = y/x z = z z = z Spherical Coordinates
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x^3 3x^2y 3xy^2y^3 (x y)^3 Solution Well you can use many methods to simplify like Using Pascal Triangle which give be 1, 3, 3, 1 as the expansion You can simplify (x y)^3 to either (x y) (x y) (x y) or (x y)^2 (x y) But using those two will result in same answer which will be in this format > 1, 3, 3, 1 Hence rArr (x y)^3 = (x y) (x y) (x y) (x y) (x y) (xThere are close connections between quaternion algebra and the algebra of vectors in 3dimensional space the components x, y and z of i, j and k respectively in the quaternion a xi yj zk can be thought of as the three components of a vector (x,y,z) in 3dimensional space, and theAnswer 3ab ⋅ 4√b 3 a b ⋅ 4 √ b Example 8 Simplify 5√− 32x3y6z5 5 √ − 32 x 3 y 6 z 5 Solution Notice that the variable factor x cannot be written as a power of 5 and thus will be left inside the radical In addition, for y6 = y5 ⋅ y y 6 = y 5 ⋅ y ;
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8 Prove the following statements (1) logp b x = 2log x (2) log p1 b p x = log x (3) log 4 x2 = log p x 9 Given that log2 = x, log3 = y and log7 = z, express the following expressions using identity a 3 b 3 c 3 3abc = (a b c)(a 2 b 2 c 2 – ab – bc – ca) if a b c = 0;(xyz)^3 (x y z) (x y z) (x y z) We multiply using the FOIL Method x * x = x^2 x * y = xy x * z = xz y * x = xy
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Simplify (xy)^3 (x − y)3 ( x y) 3 Use the Binomial Theorem x3 3x2(−y) 3x(−y)2 (−y)3 x 3 3 x 2 ( y) 3 x ( y) 2 ( y) 3 Simplify each term Tap for more steps Rewrite using the commutative property of multiplication x 3 3 ⋅ − 1 ( x 2 y) 3 x ( − y) 2 ( − y) 3 x 3 3 ⋅ 1 ( x 2 y) 3 x ( y) 2Expectations Expectations (See also Hays, Appendix B;So for example, 2^3 * 2^2 = 2^5 And likewise, 2^1 * 2^1 *2^1 = 2^3, which equals 8 Now let's try it with a variable for the exponent, where we are trying to find the cube root of 8 by raising 8 to some undetermined power 8^x * 8^x * 8^x = 8^1 = 8
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I don't know what you really want to ask , but here is at least a bit of content to this for this formula Since it is homogenous in x,y,z (so all terms have equal degree), you can read it as a description of a object of algebraic geometry either41 Multiply (zx)3 by (zx) The rule says To multiply exponential expressions which have the same base, add up their exponents In our case, the common base is (zx) and the exponents are 3 and 1 , as (zx) is the same number as (zx)1 The product is therefore, (zx)(31) = (zx)4My final answer then is 1 3 x y y ( 4 x 2) \mathbf {\color {purple} {\small { 13\mathit {xy}\sqrt {\mathit {y}\,} (4 \mathit {x}^2) }}} 13xy y (4x2) You can use the Mathway widget below to practice factoring by pulling the GCF out of each of the terms of a polynomial
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