Answer by You can put this solution on YOUR website!Multiply 5 y 9 1 6 x 3 times 8 0 x 2 y 5 by multiplying numerator times numerator and denominator times denominator Cancel out 16y^ {5} in both numerator and denominator Cancel out 1 6 y 5 in both numerator and denominator To multiply powers of the same base, add their exponents Add 2 and 3Then a 3 b 3 c 3 3abc = 0 or a 3 b 3 c 3 = 3abc
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Simplify (x^3-y^3)^3 (y^3-z^3)^3 (z^3-x^3)^3/(x-y)^3 (y-z)^3 (z-x)^3
Simplify (x^3-y^3)^3 (y^3-z^3)^3 (z^3-x^3)^3/(x-y)^3 (y-z)^3 (z-x)^3-X^3 x^2 y x y^2 y^3 Natural Language;See all questions in Exponential Properties Involving Quotients
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Solve the following system of equations for x, y and z 7x5y3z = 16 (1) 3x5y2z =8 (2) 5x3y7z = 0 (3) Answer Solution We are going to show you how to solve this system of equations three different ways 1) Substitution, 2) Elimination 3) Matrices SUBSTITUTION The process of substitution involves several stepsGet stepbystep solutions from expert tutors as fast as 1530 minutesSimplify algebraic expressions stepbystep \square!
2x 3 (yx) 2 D (yx) = 0 , 2x 3 (yx) 2 (y'1) = 0 , so that (Now solve for y' ) 2x 3 (yx) 2 y' 3 (yx) 2 = 0 , 3 (yx) 2 y' = 3 (yx) 2 2x, and Thus, the slope of the line tangent to the graph at (1, 3) is , and the equation of the tangent line is y ( 3 ) = (5/6) ( x ( 1 ) ) , or y = (5/6) x (13/6) Click HERE to return to Added PM This answer has been confirmed as correct and helpful 5 jomar07 Simplify (2x 3) (x 4) Solution Using Foil Method (2x 3) (x 4) = 2x^2 8x 3x 12 = 2x^2 5x 12Algebra Factor x^3y^3 x3 − y3 x 3 y 3 Since both terms are perfect cubes, factor using the difference of cubes formula, a3 −b3 = (a−b)(a2 abb2) a 3 b 3 = ( a b) ( a 2 a b b 2) where a = x a = x and b = y b = y (x−y)(x2 xyy2) ( x y) ( x 2 x y y 2)
1 Find the distance from the point (1, 4, 1) to the plane 2x3y z = 1 We need to nd some vector to the plane, for which we need a point in the plane If we pick x = 0 and y = 0, we get z = 1, so z = 1 Thus, (0;0;1) is a point in the plane Then we can compute a vector from the point to the plane as 2 4 1 4 1 3 5 2 4 0 0 1 3 5= 2 4 1 4 0 3 5Xx = x Proof x x = (x x) 1 postulate 2(b)Your answer would be x^4yz/3 so simplified it would be 3x^4y^4z^2/6y^3z^3 Now simplify the z's bring z^3 to the numerator And get 3 x^4 y^4 z^2 (z^3) /6y^3 z^2 (z^3) is z because when multiplying your exponents add or subtract depending on whether a number is negative or positive In this problem its like (23)= 1 and z^1 is z
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Simplify X Y Z 2 X Y 2 Z 3 2 X 2 Y 3 Z 4 2
Y z 1 Example 5608 3 Find @z @x for x 2y z 2z =4 Let's use the information from example 2 All we need to find is Fx =2x Then @z @x = 2x 2z 2 = x z 1 • Sometimes x and y are functions of one or more parameters We may find the derivative of a function with respect to that parameter using the chain rule • The formulas for3 Integrate both sides Z 1 f(y) dy = Z g(x) dx This gives us an implicit solution 4 Solve for y (if possible) This gives us an explicit solution 5 If there is an initial condition, use it to solve for the unknown parameter in the solution function 6 Check for any constant singular solutions Remember they must satisfy both the DE and341 Digital Circuits and Their Relationship to Boolean Algebra 134 • More complex Boolean expressions can be represented as combinations of AND, OR, and NOT gates, resulting in a logic diagram that describes the entire expression FIGURE 39 A Logic Diagram for F(x, y, z) = x y'z 342 Integrated Circuits 136 •
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Z= 1 2t is parallel to the plane 2x 3y 4z= 5 Solution A line is parallel to the plane if it is perpendicular to a normal vector to the plane A normal vector to the plane is given by h2;3;4iand the direction of the line is given by the vectorFirst type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More ExamplesHow do you simplify #(2^3 *3^2) / (2^4 * 3^2)^2#?
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Section 35 Minterms, Maxterms, Canonical Form & Standard Form Page 2 of 5 A maxterm, denoted as Mi, where 0 ≤ i < 2n, is a sum (OR) of the n variables (literals) in which each variable is complemented if theA = axiayjazk (314) where ax = dvx dt = d2x dt2 ay = dvy dt = d2y dt2 az = dvz dt = d2z dt2 (315) 314 Constant Acceleration in Two Dimensions When the acceleration a (for motion in two dimensions) is constant we have two sets of equations to describe the x and y coordinates, each of which is similar to the equations inY = 3 Parabola z = x2 9 (d) Sketch all the traces that you found in part (c) on the same coordinate axes 5 (e) Below is the graph of z = x2 y2 On the graph of the surface, sketch the traces that you found in parts (a) and (c) For problems 1213, nd an equation of
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X 3 Y 3 Z 3 क म न ज ञ त क ज ए यद X Y Z 15 Xy Yz Zx 71 व Xyz 10
((3 • (x y z) x 3) y 3) z 3 Step 2 Trying to factor by pulling out 21 Factoring x 3 3xy 3 3yz 3 3z Thoughtfully split the expression at hand into groups, each group having two terms Group 1 y 3 3y Group 2 x 3 3x Group 3 z 3 3z Pull out from each group separately Group 1 (y 23) • (y) Group 2 (x 23Steps for Solving Linear Equation y = 2x3 y = 2 x 3 Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x3=y 2 x 3 = y Subtract 3 from both sides Subtract 3 from both sidesSimplify (x y) 3 (x y) 3 Simplifying Mathematical Expressions There are a number of different types of mathematical expressions in the study of mathematics
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View Question If X Y Z 1 And X 2 Y 2 Z 2 3 Then Find The Value Of Xy Xz Yz
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